(6y^2+5)+(-3y^2-8)=3y^2+5

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Solution for (6y^2+5)+(-3y^2-8)=3y^2+5 equation:


Simplifying
(6y2 + 5) + (-3y2 + -8) = 3y2 + 5

Reorder the terms:
(5 + 6y2) + (-3y2 + -8) = 3y2 + 5

Remove parenthesis around (5 + 6y2)
5 + 6y2 + (-3y2 + -8) = 3y2 + 5

Reorder the terms:
5 + 6y2 + (-8 + -3y2) = 3y2 + 5

Remove parenthesis around (-8 + -3y2)
5 + 6y2 + -8 + -3y2 = 3y2 + 5

Reorder the terms:
5 + -8 + 6y2 + -3y2 = 3y2 + 5

Combine like terms: 5 + -8 = -3
-3 + 6y2 + -3y2 = 3y2 + 5

Combine like terms: 6y2 + -3y2 = 3y2
-3 + 3y2 = 3y2 + 5

Reorder the terms:
-3 + 3y2 = 5 + 3y2

Add '-3y2' to each side of the equation.
-3 + 3y2 + -3y2 = 5 + 3y2 + -3y2

Combine like terms: 3y2 + -3y2 = 0
-3 + 0 = 5 + 3y2 + -3y2
-3 = 5 + 3y2 + -3y2

Combine like terms: 3y2 + -3y2 = 0
-3 = 5 + 0
-3 = 5

Solving
-3 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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